Solve -16(1/2)^4+4(1/2)^2+8(1/2)-9

$$- 16 ( \frac { 1 } { 2 } ) ^ { 4 } + 4 ( \frac { 1 } { 2 } ) ^ { 2 } + 8 ( \frac { 1 } { 2 } ) - 9$$

Evaluate

$$-5$$

Solution Steps

Calculate \frac{1}{2} to the power of 4 and get \frac{1}{16}.

$$-16\times \frac{1}{16}+4\times \left(\frac{1}{2}\right)^{2}+8\times \frac{1}{2}-9$$

Multiply -16 times \frac{1}{16}.

$$-1+4\times \left(\frac{1}{2}\right)^{2}+8\times \frac{1}{2}-9$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$-1+4\times \frac{1}{4}+8\times \frac{1}{2}-9$$

Cancel out 4 and 4.

$$-1+1+8\times \frac{1}{2}-9$$

Add -1 and 1 to get 0.

$$8\times \frac{1}{2}-9$$

Multiply 8 and \frac{1}{2} to get \frac{8}{2}.

$$\frac{8}{2}-9$$

Divide 8 by 2 to get 4.

$$4-9$$

Subtract 9 from 4 to get -5.

$$-5$$

Factor

$$-5$$