Solve -15x+5y-45=0

$$- 15 x + 5 y - 45 = 0$$

Solve for x

$$x=\frac{y-9}{3}$$

Steps for Solving Linear Equation

Subtract 5y from both sides. Anything subtracted from zero gives its negation.

$$-15x-45=-5y$$

Add 45 to both sides.

$$-15x=-5y+45$$

The equation is in standard form.

$$-15x=45-5y$$

Divide both sides by -15.

$$\frac{-15x}{-15}=\frac{45-5y}{-15}$$

Dividing by -15 undoes the multiplication by -15.

$$x=\frac{45-5y}{-15}$$

Divide -5y+45 by -15.

$$x=\frac{y}{3}-3$$

Solve for y

$$y=3\left(x+3\right)$$

Steps for Solving Linear Equation

Add 15x to both sides. Anything plus zero gives itself.

$$5y-45=15x$$

Add 45 to both sides.

$$5y=15x+45$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{15x+45}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{15x+45}{5}$$

Divide 45+15x by 5.

$$y=3x+9$$