Solve -136x^2+2720x-10752=0

$$- 136 x ^ { 2 } + 2720 x - 10752 = 0$$

Solve for x

$$x=\frac{2\sqrt{1513}}{17}+10\approx 14.576153021$$

$$x=-\frac{2\sqrt{1513}}{17}+10\approx 5.423846979$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$-136x^{2}+2720x-10752=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -136 for a, 2720 for b, and -10752 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-2720±\sqrt{2720^{2}-4\left(-136\right)\left(-10752\right)}}{2\left(-136\right)}$$

Square 2720.

$$x=\frac{-2720±\sqrt{7398400-4\left(-136\right)\left(-10752\right)}}{2\left(-136\right)}$$

Multiply -4 times -136.

$$x=\frac{-2720±\sqrt{7398400+544\left(-10752\right)}}{2\left(-136\right)}$$

Multiply 544 times -10752.

$$x=\frac{-2720±\sqrt{7398400-5849088}}{2\left(-136\right)}$$

Add 7398400 to -5849088.

$$x=\frac{-2720±\sqrt{1549312}}{2\left(-136\right)}$$

Take the square root of 1549312.

$$x=\frac{-2720±32\sqrt{1513}}{2\left(-136\right)}$$

Multiply 2 times -136.

$$x=\frac{-2720±32\sqrt{1513}}{-272}$$

Now solve the equation x=\frac{-2720±32\sqrt{1513}}{-272} when ± is plus. Add -2720 to 32\sqrt{1513}.

$$x=\frac{32\sqrt{1513}-2720}{-272}$$

Divide -2720+32\sqrt{1513} by -272.

$$x=-\frac{2\sqrt{1513}}{17}+10$$

Now solve the equation x=\frac{-2720±32\sqrt{1513}}{-272} when ± is minus. Subtract 32\sqrt{1513} from -2720.

$$x=\frac{-32\sqrt{1513}-2720}{-272}$$

Divide -2720-32\sqrt{1513} by -272.

$$x=\frac{2\sqrt{1513}}{17}+10$$

The equation is now solved.

$$x=-\frac{2\sqrt{1513}}{17}+10 x=\frac{2\sqrt{1513}}{17}+10$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$-136x^{2}+2720x-10752=0$$

Add 10752 to both sides of the equation.

$$-136x^{2}+2720x-10752-\left(-10752\right)=-\left(-10752\right)$$

Subtracting -10752 from itself leaves 0.

$$-136x^{2}+2720x=-\left(-10752\right)$$

Subtract -10752 from 0.

$$-136x^{2}+2720x=10752$$

Divide both sides by -136.

$$\frac{-136x^{2}+2720x}{-136}=\frac{10752}{-136}$$

Dividing by -136 undoes the multiplication by -136.

$$x^{2}+\frac{2720}{-136}x=\frac{10752}{-136}$$

Divide 2720 by -136.

$$x^{2}-20x=\frac{10752}{-136}$$

Reduce the fraction \frac{10752}{-136} to lowest terms by extracting and canceling out 8.

$$x^{2}-20x=-\frac{1344}{17}$$

Divide -20, the coefficient of the x term, by 2 to get -10. Then add the square of -10 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-20x+\left(-10\right)^{2}=-\frac{1344}{17}+\left(-10\right)^{2}$$

Square -10.

$$x^{2}-20x+100=-\frac{1344}{17}+100$$

Add -\frac{1344}{17} to 100.

$$x^{2}-20x+100=\frac{356}{17}$$

Factor x^{2}-20x+100. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-10\right)^{2}=\frac{356}{17}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-10\right)^{2}}=\sqrt{\frac{356}{17}}$$

Simplify.

$$x-10=\frac{2\sqrt{1513}}{17} x-10=-\frac{2\sqrt{1513}}{17}$$

Add 10 to both sides of the equation.

$$x=\frac{2\sqrt{1513}}{17}+10 x=-\frac{2\sqrt{1513}}{17}+10$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.

$$x ^ 2 -20x +\frac{1344}{17} = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = 20 rs = \frac{1344}{17}$$

Two numbers r and s sum up to 20 exactly when the average of the two numbers is \frac{1}{2}*20 = 10. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = 10 - u s = 10 + u$$

To solve for unknown quantity u, substitute these in the product equation rs = \frac{1344}{17}

$$(10 - u) (10 + u) = \frac{1344}{17}$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$100 - u^2 = \frac{1344}{17}$$

Simplify the expression by subtracting 100 on both sides

$$-u^2 = \frac{1344}{17}-100 = -\frac{356}{17}$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = \frac{356}{17} u = \pm\sqrt{\frac{356}{17}} = \pm \frac{\sqrt{356}}{\sqrt{17}}$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =10 - \frac{\sqrt{356}}{\sqrt{17}} = 5.424 s = 10 + \frac{\sqrt{356}}{\sqrt{17}} = 14.576$$