Solve for x
x=\frac{4-2y}{3}
Solve for y
y=-\frac{3x}{2}+2
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-12x=-16+8y
Add 8y to both sides.
-12x=8y-16
The equation is in standard form.
\frac{-12x}{-12}=\frac{8y-16}{-12}
Divide both sides by -12.
x=\frac{8y-16}{-12}
Dividing by -12 undoes the multiplication by -12.
x=\frac{4-2y}{3}
Divide -16+8y by -12.
-8y=-16+12x
Add 12x to both sides.
-8y=12x-16
The equation is in standard form.
\frac{-8y}{-8}=\frac{12x-16}{-8}
Divide both sides by -8.
y=\frac{12x-16}{-8}
Dividing by -8 undoes the multiplication by -8.
y=-\frac{3x}{2}+2
Divide -16+12x by -8.
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