Solve for x
x=\frac{7y}{6}-\frac{1}{3}
Solve for y
y=\frac{6x+2}{7}
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-12x=4-14y
Subtract 14y from both sides.
\frac{-12x}{-12}=\frac{4-14y}{-12}
Divide both sides by -12.
x=\frac{4-14y}{-12}
Dividing by -12 undoes the multiplication by -12.
x=\frac{7y}{6}-\frac{1}{3}
Divide 4-14y by -12.
14y=4+12x
Add 12x to both sides.
14y=12x+4
The equation is in standard form.
\frac{14y}{14}=\frac{12x+4}{14}
Divide both sides by 14.
y=\frac{12x+4}{14}
Dividing by 14 undoes the multiplication by 14.
y=\frac{6x+2}{7}
Divide 4+12x by 14.
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