Solve -10^2div1/2*2/5+(-10)*(-3)^2

$$- 10 ^ { 2 } \div \frac { 1 } { 2 } \times \frac { 2 } { 5 } + ( - 10 ) \times ( - 3 ) ^ { 2 }$$

Evaluate

$$-170$$

Solution Steps

Calculate 10 to the power of 2 and get 100.

$$\frac{-100}{\frac{1}{2}}\times \frac{2}{5}-10\left(-3\right)^{2}$$

Divide -100 by \frac{1}{2} by multiplying -100 by the reciprocal of \frac{1}{2}.

$$-100\times 2\times \frac{2}{5}-10\left(-3\right)^{2}$$

Multiply -100 and 2 to get -200.

$$-200\times \frac{2}{5}-10\left(-3\right)^{2}$$

Express -200\times \frac{2}{5} as a single fraction.

$$\frac{-200\times 2}{5}-10\left(-3\right)^{2}$$

Multiply -200 and 2 to get -400.

$$\frac{-400}{5}-10\left(-3\right)^{2}$$

Divide -400 by 5 to get -80.

$$-80-10\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$-80-10\times 9$$

Multiply -10 and 9 to get -90.

$$-80-90$$

Subtract 90 from -80 to get -170.

$$-170$$

Factor

$$-170$$