Solve -1,9-5,7xleq0

$$- 1,9 - 5,7 x \leq 0$$

Solve for x

$$x\geq -\frac{1}{3}$$

Solution Steps

Add 1,9 to both sides. Anything plus zero gives itself.

$$-5,7x\leq 1,9$$

Divide both sides by -5,7. Since -5,7 is negative, the inequality direction is changed.

$$x\geq \frac{1,9}{-5,7}$$

Expand \frac{1,9}{-5,7} by multiplying both numerator and the denominator by 10.

$$x\geq \frac{19}{-57}$$

Reduce the fraction \frac{19}{-57} to lowest terms by extracting and canceling out 19.

$$x\geq -\frac{1}{3}$$