Solve -17/9:(-2/3)^3

$$- 1 \frac { 7 } { 9 } : ( - \frac { 2 } { 3 } ) ^ { 3 }$$

Evaluate

$$6$$

Solution Steps

Multiply 1 and 9 to get 9.

$$\frac{-\frac{9+7}{9}}{\left(-\frac{2}{3}\right)^{3}}$$

Add 9 and 7 to get 16.

$$\frac{-\frac{16}{9}}{\left(-\frac{2}{3}\right)^{3}}$$

Calculate -\frac{2}{3} to the power of 3 and get -\frac{8}{27}.

$$\frac{-\frac{16}{9}}{-\frac{8}{27}}$$

Divide -\frac{16}{9} by -\frac{8}{27} by multiplying -\frac{16}{9} by the reciprocal of -\frac{8}{27}.

$$-\frac{16}{9}\left(-\frac{27}{8}\right)$$

Multiply -\frac{16}{9} times -\frac{27}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-16\left(-27\right)}{9\times 8}$$

Do the multiplications in the fraction \frac{-16\left(-27\right)}{9\times 8}.

$$\frac{432}{72}$$

Divide 432 by 72 to get 6.

$$6$$

Factor

$$2\times 3$$