Solve -1*[(-4)+(-2)*(-6)+(-6-4):2]-(2-5)

$$- 1 \cdot [ ( - 4 ) + ( - 2 ) \cdot ( - 6 ) + ( - 6 - 4 ) : 2 ] - ( 2 - 5 )$$

Evaluate

$$0$$

Solution Steps

Multiply -2 and -6 to get 12.

$$-\left(-4+12+\frac{-6-4}{2}\right)-\left(2-5\right)$$

Add -4 and 12 to get 8.

$$-\left(8+\frac{-6-4}{2}\right)-\left(2-5\right)$$

Subtract 4 from -6 to get -10.

$$-\left(8+\frac{-10}{2}\right)-\left(2-5\right)$$

Divide -10 by 2 to get -5.

$$-\left(8-5\right)-\left(2-5\right)$$

Subtract 5 from 8 to get 3.

$$-3-\left(2-5\right)$$

Subtract 5 from 2 to get -3.

$$-3-\left(-3\right)$$

The opposite of -3 is 3.

$$-3+3$$

Add -3 and 3 to get 0.

$$0$$

Factor

$$0$$