Solve -1^4-(1-0.5)*1/3*[1-(-2)^2]

$$- 1 ^ { 4 } - ( 1 - 0.5 ) \times \frac { 1 } { 3 } \times [ 1 - ( - 2 ) ^ { 2 } ]$$

Evaluate

$$-0.5$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$-1-\left(1-0.5\right)\times \frac{1}{3}\left(1-\left(-2\right)^{2}\right)$$

Subtract 0.5 from 1 to get 0.5.

$$-1-0.5\times \frac{1}{3}\left(1-\left(-2\right)^{2}\right)$$

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$-1-\frac{1}{2}\times \frac{1}{3}\left(1-\left(-2\right)^{2}\right)$$

Multiply \frac{1}{2} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$-1-\frac{1\times 1}{2\times 3}\left(1-\left(-2\right)^{2}\right)$$

Do the multiplications in the fraction \frac{1\times 1}{2\times 3}.

$$-1-\frac{1}{6}\left(1-\left(-2\right)^{2}\right)$$

Calculate -2 to the power of 2 and get 4.

$$-1-\frac{1}{6}\left(1-4\right)$$

Subtract 4 from 1 to get -3.

$$-1-\frac{1}{6}\left(-3\right)$$

Multiply \frac{1}{6} and -3 to get \frac{-3}{6}.

$$-1-\frac{-3}{6}$$

Reduce the fraction \frac{-3}{6} to lowest terms by extracting and canceling out 3.

$$-1-\left(-\frac{1}{2}\right)$$

The opposite of -\frac{1}{2} is \frac{1}{2}.

$$-1+\frac{1}{2}$$

Convert -1 to fraction -\frac{2}{2}.

$$-\frac{2}{2}+\frac{1}{2}$$

Since -\frac{2}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{-2+1}{2}$$

Add -2 and 1 to get -1.

$$-\frac{1}{2}$$

Factor

$$-0.5$$