Solve -1^4+16div(-2)^3*|-3-1|

$$- 1 ^ { 4 } + 16 \div ( - 2 ) ^ { 3 } \times | - 3 - 1 |$$

Evaluate

$$-9$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$-1+\frac{16}{\left(-2\right)^{3}}|-3-1|$$

Calculate -2 to the power of 3 and get -8.

$$-1+\frac{16}{-8}|-3-1|$$

Divide 16 by -8 to get -2.

$$-1-2|-3-1|$$

Subtract 1 from -3 to get -4.

$$-1-2|-4|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.

$$-1-2\times 4$$

Multiply -2 and 4 to get -8.

$$-1-8$$

Subtract 8 from -1 to get -9.

$$-9$$

Factor

$$-9$$