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-1-\sqrt{8}+\left(\frac{1}{2}\right)^{-1}+\left(\sqrt{3}-\sqrt{2}\right)^{0}
Calculate 1 to the power of 2020 and get 1.
-1-2\sqrt{2}+\left(\frac{1}{2}\right)^{-1}+\left(\sqrt{3}-\sqrt{2}\right)^{0}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
-1-2\sqrt{2}+2+\left(\sqrt{3}-\sqrt{2}\right)^{0}
Calculate \frac{1}{2} to the power of -1 and get 2.
1-2\sqrt{2}+\left(\sqrt{3}-\sqrt{2}\right)^{0}
Add -1 and 2 to get 1.
1-2\sqrt{2}+1
Calculate \sqrt{3}-\sqrt{2} to the power of 0 and get 1.
2-2\sqrt{2}
Add 1 and 1 to get 2.