Solve -1^2018+24div(-2)^2-3^2*(1/3)^2

$$- 1 ^ { 2018 } + 24 \div ( - 2 ) ^ { 2 } - 3 ^ { 2 } \times ( \frac { 1 } { 3 } ) ^ { 2 }$$

Evaluate

$$4$$

Solution Steps

Calculate 1 to the power of 2018 and get 1.

$$-1+\frac{24}{\left(-2\right)^{2}}-3^{2}\times \left(\frac{1}{3}\right)^{2}$$

Calculate -2 to the power of 2 and get 4.

$$-1+\frac{24}{4}-3^{2}\times \left(\frac{1}{3}\right)^{2}$$

Divide 24 by 4 to get 6.

$$-1+6-3^{2}\times \left(\frac{1}{3}\right)^{2}$$

Add -1 and 6 to get 5.

$$5-3^{2}\times \left(\frac{1}{3}\right)^{2}$$

Calculate 3 to the power of 2 and get 9.

$$5-9\times \left(\frac{1}{3}\right)^{2}$$

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$5-9\times \frac{1}{9}$$

Cancel out 9 and 9.

$$5-1$$

Subtract 1 from 5 to get 4.

$$4$$

Factor

$$2^{2}$$