Solve -1^2000-sqrt{9}+2+(1/3)^-1-(-2020)^0=

$$- 1 ^ { 2000 } - \sqrt { 9 } + 2 + ( \frac { 1 } { 3 } ) ^ { - 1 } - ( - 2020 ) ^ { 0 } =$$

Evaluate

$$0$$

Solution Steps

Calculate 1 to the power of 2000 and get 1.

$$-1-\sqrt{9}+2+\left(\frac{1}{3}\right)^{-1}-\left(-2020\right)^{0}$$

Calculate the square root of 9 and get 3.

$$-1-3+2+\left(\frac{1}{3}\right)^{-1}-\left(-2020\right)^{0}$$

Subtract 3 from -1 to get -4.

$$-4+2+\left(\frac{1}{3}\right)^{-1}-\left(-2020\right)^{0}$$

Add -4 and 2 to get -2.

$$-2+\left(\frac{1}{3}\right)^{-1}-\left(-2020\right)^{0}$$

Calculate \frac{1}{3} to the power of -1 and get 3.

$$-2+3-\left(-2020\right)^{0}$$

Add -2 and 3 to get 1.

$$1-\left(-2020\right)^{0}$$

Calculate -2020 to the power of 0 and get 1.

$$1-1$$

Subtract 1 from 1 to get 0.

$$0$$

Factor

$$0$$