Solve -1^2-1/3-3+3^2

$$- 1 ^ { 2 } - \frac { 1 } { 3 } - 3 + 3 ^ { 2 }$$

Evaluate

$$\frac{14}{3}\approx 4.666666667$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$-1-\frac{1}{3}-3+3^{2}$$

Convert -1 to fraction -\frac{3}{3}.

$$-\frac{3}{3}-\frac{1}{3}-3+3^{2}$$

Since -\frac{3}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-1}{3}-3+3^{2}$$

Subtract 1 from -3 to get -4.

$$-\frac{4}{3}-3+3^{2}$$

Convert 3 to fraction \frac{9}{3}.

$$-\frac{4}{3}-\frac{9}{3}+3^{2}$$

Since -\frac{4}{3} and \frac{9}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4-9}{3}+3^{2}$$

Subtract 9 from -4 to get -13.

$$-\frac{13}{3}+3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$-\frac{13}{3}+9$$

Convert 9 to fraction \frac{27}{3}.

$$-\frac{13}{3}+\frac{27}{3}$$

Since -\frac{13}{3} and \frac{27}{3} have the same denominator, add them by adding their numerators.

$$\frac{-13+27}{3}$$

Add -13 and 27 to get 14.

$$\frac{14}{3}$$

Factor

$$\frac{2 \cdot 7}{3} = 4\frac{2}{3} = 4.666666666666667$$