Solve -1^2[(-4)+(-2)^4(-6)+(-6-4):2]-(2-5)

$$- 1 ^ { 2 } [ ( - 4 ) + ( - 2 ) ^ { 4 } ( - 6 ) + ( - 6 - 4 ) : 2 ] - ( 2 - 5 )$$

Evaluate

$$108$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$-\left(-4+\left(-2\right)^{4}\left(-6\right)+\frac{-6-4}{2}\right)-\left(2-5\right)$$

Calculate -2 to the power of 4 and get 16.

$$-\left(-4+16\left(-6\right)+\frac{-6-4}{2}\right)-\left(2-5\right)$$

Multiply 16 and -6 to get -96.

$$-\left(-4-96+\frac{-6-4}{2}\right)-\left(2-5\right)$$

Subtract 96 from -4 to get -100.

$$-\left(-100+\frac{-6-4}{2}\right)-\left(2-5\right)$$

Subtract 4 from -6 to get -10.

$$-\left(-100+\frac{-10}{2}\right)-\left(2-5\right)$$

Divide -10 by 2 to get -5.

$$-\left(-100-5\right)-\left(2-5\right)$$

Subtract 5 from -100 to get -105.

$$-\left(-105\right)-\left(2-5\right)$$

Multiply -1 and -105 to get 105.

$$105-\left(2-5\right)$$

Subtract 5 from 2 to get -3.

$$105-\left(-3\right)$$

The opposite of -3 is 3.

$$105+3$$

Add 105 and 3 to get 108.

$$108$$

Factor

$$2^{2}\times 3^{3}$$