Solve for x
x = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333
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-3x-\left(-12\right)=9x-4
To find the opposite of 3x-12, find the opposite of each term.
-3x+12=9x-4
The opposite of -12 is 12.
-3x+12-9x=-4
Subtract 9x from both sides.
-12x+12=-4
Combine -3x and -9x to get -12x.
-12x=-4-12
Subtract 12 from both sides.
-12x=-16
Subtract 12 from -4 to get -16.
x=\frac{-16}{-12}
Divide both sides by -12.
x=\frac{4}{3}
Reduce the fraction \frac{-16}{-12} to lowest terms by extracting and canceling out -4.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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