Solve -(2y+3)-(4y-1)=-12-(3y+2)

$$- ( 2 y + 3 ) - ( 4 y - 1 ) = - 12 - ( 3 y + 2 )$$

Solve for y

$$y=4$$

Steps for Solving Linear Equation

To find the opposite of 2y+3, find the opposite of each term.

$$-2y-3-\left(4y-1\right)=-12-\left(3y+2\right)$$

To find the opposite of 4y-1, find the opposite of each term.

$$-2y-3-4y-\left(-1\right)=-12-\left(3y+2\right)$$

The opposite of -1 is 1.

$$-2y-3-4y+1=-12-\left(3y+2\right)$$

Combine -2y and -4y to get -6y.

$$-6y-3+1=-12-\left(3y+2\right)$$

Add -3 and 1 to get -2.

$$-6y-2=-12-\left(3y+2\right)$$

To find the opposite of 3y+2, find the opposite of each term.

$$-6y-2=-12-3y-2$$

Subtract 2 from -12 to get -14.

$$-6y-2=-14-3y$$

Add 3y to both sides.

$$-6y-2+3y=-14$$

Combine -6y and 3y to get -3y.

$$-3y-2=-14$$

Add 2 to both sides.

$$-3y=-14+2$$

Add -14 and 2 to get -12.

$$-3y=-12$$

Divide both sides by -3.

$$y=\frac{-12}{-3}$$

Divide -12 by -3 to get 4.

$$y=4$$