Solve -(2x^2y)^3quadtext{(2)}(p^2q)

$$- ( 2 x ^ { 2 } y ) ^ { 3 } \quad \text { (2) } ( p ^ { 2 } q )$$

Evaluate

$$-16qp^{2}y^{3}x^{6}$$

Solution Steps

Expand \left(2x^{2}y\right)^{3}.

$$\left(-2^{3}\left(x^{2}\right)^{3}y^{3}\right)\times 2p^{2}q$$

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$\left(-2^{3}x^{6}y^{3}\right)\times 2p^{2}q$$

Calculate 2 to the power of 3 and get 8.

$$\left(-8x^{6}y^{3}\right)\times 2p^{2}q$$

Multiply -1 and 8 to get -8.

$$-8x^{6}y^{3}\times 2p^{2}q$$

Multiply -8 and 2 to get -16.

$$-16x^{6}y^{3}p^{2}q$$

Expand

$$-16qp^{2}y^{3}x^{6}$$

Solution Steps

Expand \left(2x^{2}y\right)^{3}.

$$\left(-2^{3}\left(x^{2}\right)^{3}y^{3}\right)\times 2p^{2}q$$

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$\left(-2^{3}x^{6}y^{3}\right)\times 2p^{2}q$$

Calculate 2 to the power of 3 and get 8.

$$\left(-8x^{6}y^{3}\right)\times 2p^{2}q$$

Multiply -1 and 8 to get -8.

$$-8x^{6}y^{3}\times 2p^{2}q$$

Multiply -8 and 2 to get -16.

$$-16x^{6}y^{3}p^{2}q$$