Solve -(-2)^2+sqrt{(-2)^2}-sqrt[3]{-8^2}

$$- ( - 2 ) ^ { 2 } + \sqrt { ( - 2 ) ^ { 2 } } - \sqrt[ 3 ] { - 8 ^ { 2 } }$$

Evaluate

$$2$$

Solution Steps

Calculate -2 to the power of 2 and get 4.

$$-4+\sqrt{\left(-2\right)^{2}}-\sqrt[3]{-8^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$-4+\sqrt{4}-\sqrt[3]{-8^{2}}$$

Calculate the square root of 4 and get 2.

$$-4+2-\sqrt[3]{-8^{2}}$$

Add -4 and 2 to get -2.

$$-2-\sqrt[3]{-8^{2}}$$

Calculate 8 to the power of 2 and get 64.

$$-2-\sqrt[3]{-64}$$

Calculate \sqrt[3]{-64} and get -4.

$$-2-\left(-4\right)$$

The opposite of -4 is 4.

$$-2+4$$

Add -2 and 4 to get 2.

$$2$$

Factor

$$2$$