Solve -(1/3)^2*(1/3)^1*(1/3)^0=

$$- ( \frac { 1 } { 3 } ) ^ { 2 } \times ( \frac { 1 } { 3 } ) ^ { 1 } \times ( \frac { 1 } { 3 } ) ^ { 0 } =$$

Evaluate

$$-\frac{1}{27}\approx -0.037037037$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 0 to get 1.

$$\left(-\left(\frac{1}{3}\right)^{2}\right)\times \left(\frac{1}{3}\right)^{1}$$

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$-\frac{1}{9}\times \left(\frac{1}{3}\right)^{1}$$

Calculate \frac{1}{3} to the power of 1 and get \frac{1}{3}.

$$-\frac{1}{9}\times \frac{1}{3}$$

Multiply -\frac{1}{9} and \frac{1}{3} to get -\frac{1}{27}.

$$-\frac{1}{27}$$

Factor

$$-\frac{1}{27} = -0.037037037037037035$$