Solve -x^2+x+30=-60

$$- { x }^{ 2 } +x+30=-60$$

Solve for x

$$x=-9$$

$$x=10$$

Steps Using Factoring By Grouping

Add 60 to both sides.

$$-x^{2}+x+30+60=0$$

Add 30 and 60 to get 90.

$$-x^{2}+x+90=0$$

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx+90. To find a and b, set up a system to be solved.

$$a+b=1 ab=-90=-90$$

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -90.

$$-1,90 -2,45 -3,30 -5,18 -6,15 -9,10$$

Calculate the sum for each pair.

$$-1+90=89 -2+45=43 -3+30=27 -5+18=13 -6+15=9 -9+10=1$$

The solution is the pair that gives sum 1.

$$a=10 b=-9$$

Rewrite -x^{2}+x+90 as \left(-x^{2}+10x\right)+\left(-9x+90\right).

$$\left(-x^{2}+10x\right)+\left(-9x+90\right)$$

Factor out -x in the first and -9 in the second group.

$$-x\left(x-10\right)-9\left(x-10\right)$$

Factor out common term x-10 by using distributive property.

$$\left(x-10\right)\left(-x-9\right)$$

To find equation solutions, solve x-10=0 and -x-9=0.

$$x=10 x=-9$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$-x^{2}+x+30=-60$$

Add 60 to both sides of the equation.

$$-x^{2}+x+30-\left(-60\right)=-60-\left(-60\right)$$

Subtracting -60 from itself leaves 0.

$$-x^{2}+x+30-\left(-60\right)=0$$

Subtract -60 from 30.

$$-x^{2}+x+90=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 1 for b, and 90 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-1±\sqrt{1^{2}-4\left(-1\right)\times 90}}{2\left(-1\right)}$$

Square 1.

$$x=\frac{-1±\sqrt{1-4\left(-1\right)\times 90}}{2\left(-1\right)}$$

Multiply -4 times -1.

$$x=\frac{-1±\sqrt{1+4\times 90}}{2\left(-1\right)}$$

Multiply 4 times 90.

$$x=\frac{-1±\sqrt{1+360}}{2\left(-1\right)}$$

Add 1 to 360.

$$x=\frac{-1±\sqrt{361}}{2\left(-1\right)}$$

Take the square root of 361.

$$x=\frac{-1±19}{2\left(-1\right)}$$

Multiply 2 times -1.

$$x=\frac{-1±19}{-2}$$

Now solve the equation x=\frac{-1±19}{-2} when ± is plus. Add -1 to 19.

$$x=\frac{18}{-2}$$

Divide 18 by -2.

$$x=-9$$

Now solve the equation x=\frac{-1±19}{-2} when ± is minus. Subtract 19 from -1.

$$x=-\frac{20}{-2}$$

Divide -20 by -2.

$$x=10$$

The equation is now solved.

$$x=-9 x=10$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$-x^{2}+x+30=-60$$

Subtract 30 from both sides of the equation.

$$-x^{2}+x+30-30=-60-30$$

Subtracting 30 from itself leaves 0.

$$-x^{2}+x=-60-30$$

Subtract 30 from -60.

$$-x^{2}+x=-90$$

Divide both sides by -1.

$$\frac{-x^{2}+x}{-1}=-\frac{90}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x^{2}+\frac{1}{-1}x=-\frac{90}{-1}$$

Divide 1 by -1.

$$x^{2}-x=-\frac{90}{-1}$$

Divide -90 by -1.

$$x^{2}-x=90$$

Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-x+\left(-\frac{1}{2}\right)^{2}=90+\left(-\frac{1}{2}\right)^{2}$$

Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-x+\frac{1}{4}=90+\frac{1}{4}$$

Add 90 to \frac{1}{4}.

$$x^{2}-x+\frac{1}{4}=\frac{361}{4}$$

Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{1}{2}\right)^{2}=\frac{361}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{361}{4}}$$

Simplify.

$$x-\frac{1}{2}=\frac{19}{2} x-\frac{1}{2}=-\frac{19}{2}$$

Add \frac{1}{2} to both sides of the equation.

$$x=10 x=-9$$