Solve -2^3div4/9-18*4/9

$$- { 2 }^{ 3 } \div \frac{ 4 }{ 9 } -18 \times \frac{ 4 }{ 9 }$$

Evaluate

$$-26$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{-8}{\frac{4}{9}}-18\times \frac{4}{9}$$

Divide -8 by \frac{4}{9} by multiplying -8 by the reciprocal of \frac{4}{9}.

$$-8\times \frac{9}{4}-18\times \frac{4}{9}$$

Express -8\times \frac{9}{4} as a single fraction.

$$\frac{-8\times 9}{4}-18\times \frac{4}{9}$$

Multiply -8 and 9 to get -72.

$$\frac{-72}{4}-18\times \frac{4}{9}$$

Divide -72 by 4 to get -18.

$$-18-18\times \frac{4}{9}$$

Express 18\times \frac{4}{9} as a single fraction.

$$-18-\frac{18\times 4}{9}$$

Multiply 18 and 4 to get 72.

$$-18-\frac{72}{9}$$

Divide 72 by 9 to get 8.

$$-18-8$$

Subtract 8 from -18 to get -26.

$$-26$$

Factor

$$-26$$