Solve -left(9+3right)^2+left(2^2right)^3-sqrt{16+9}

$$- { \left(9+3 \right) }^{ 2 } + { \left( { 2 }^{ 2 } \right) }^{ 3 } - \sqrt{ 16+9 }$$

Evaluate

$$-85$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$-\left(9+3\right)^{2}+2^{6}-\sqrt{16+9}$$

Add 9 and 3 to get 12.

$$-12^{2}+2^{6}-\sqrt{16+9}$$

Calculate 12 to the power of 2 and get 144.

$$-144+2^{6}-\sqrt{16+9}$$

Calculate 2 to the power of 6 and get 64.

$$-144+64-\sqrt{16+9}$$

Add -144 and 64 to get -80.

$$-80-\sqrt{16+9}$$

Add 16 and 9 to get 25.

$$-80-\sqrt{25}$$

Calculate the square root of 25 and get 5.

$$-80-5$$

Subtract 5 from -80 to get -85.

$$-85$$

Factor

$$-85$$