Solve -1/2*(432*4)-1/2*(239*4)+(428*4)=

$$- \frac{ 1 }{ 2 } \times (432 \times 4)- \frac{ 1 }{ 2 } \times (239 \times 4)+(428 \times 4)=$$

Evaluate

$$370$$

Solution Steps

Express -\frac{1}{2}\times 432 as a single fraction.

$$\frac{-432}{2}\times 4-\frac{1}{2}\times 239\times 4+428\times 4$$

Divide -432 by 2 to get -216.

$$-216\times 4-\frac{1}{2}\times 239\times 4+428\times 4$$

Multiply -216 and 4 to get -864.

$$-864-\frac{1}{2}\times 239\times 4+428\times 4$$

Multiply \frac{1}{2} and 239 to get \frac{239}{2}.

$$-864-\frac{239}{2}\times 4+428\times 4$$

Express \frac{239}{2}\times 4 as a single fraction.

$$-864-\frac{239\times 4}{2}+428\times 4$$

Multiply 239 and 4 to get 956.

$$-864-\frac{956}{2}+428\times 4$$

Divide 956 by 2 to get 478.

$$-864-478+428\times 4$$

Subtract 478 from -864 to get -1342.

$$-1342+428\times 4$$

Multiply 428 and 4 to get 1712.

$$-1342+1712$$

Add -1342 and 1712 to get 370.

$$370$$

Factor

$$2\times 5\times 37$$