Solve -frac{left(7(6)-105right){e}^frac{-(6){15}}}{15}

$$- \frac{ \left( 7(6)-105 \right) { e }^{ \frac{ -(6) }{ 15 } } }{ 15 }$$

Evaluate

$$\frac{21}{5e^{\frac{2}{5}}}\approx 2.815344193$$

Solution Steps

Multiply 7 and 6 to get 42.

$$-\frac{\left(42-105\right)e^{\frac{-6}{15}}}{15}$$

Subtract 105 from 42 to get -63.

$$-\frac{-63e^{\frac{-6}{15}}}{15}$$

Reduce the fraction \frac{-6}{15} to lowest terms by extracting and canceling out 3.

$$-\frac{-63e^{-\frac{2}{5}}}{15}$$

Divide -63e^{-\frac{2}{5}} by 15 to get -\frac{21}{5}e^{-\frac{2}{5}}.

$$-\left(-\frac{21}{5}e^{-\frac{2}{5}}\right)$$

The opposite of -\frac{21}{5}e^{-\frac{2}{5}} is \frac{21}{5}e^{-\frac{2}{5}}.

$$\frac{21}{5}e^{-\frac{2}{5}}$$