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\frac{y+1}{y-1}\leq 0
Divide both sides by -1. Since -1 is negative, the inequality direction is changed. Zero divided by any non-zero number gives zero.
y+1\geq 0 y-1<0
For the quotient to be ≤0, one of the values y+1 and y-1 has to be ≥0, the other has to be ≤0, and y-1 cannot be zero. Consider the case when y+1\geq 0 and y-1 is negative.
y\in [-1,1)
The solution satisfying both inequalities is y\in \left[-1,1\right).
y+1\leq 0 y-1>0
Consider the case when y+1\leq 0 and y-1 is positive.
y\in \emptyset
This is false for any y.
y\in [-1,1)
The final solution is the union of the obtained solutions.