Solve for x
x=\frac{-4y-8}{5}
Solve for y
y=-\frac{5x}{4}-2
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-\frac{5}{4}x=2+y
Add y to both sides.
-\frac{5}{4}x=y+2
The equation is in standard form.
\frac{-\frac{5}{4}x}{-\frac{5}{4}}=\frac{y+2}{-\frac{5}{4}}
Divide both sides of the equation by -\frac{5}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y+2}{-\frac{5}{4}}
Dividing by -\frac{5}{4} undoes the multiplication by -\frac{5}{4}.
x=\frac{-4y-8}{5}
Divide 2+y by -\frac{5}{4} by multiplying 2+y by the reciprocal of -\frac{5}{4}.
-y=2+\frac{5}{4}x
Add \frac{5}{4}x to both sides.
-y=\frac{5x}{4}+2
The equation is in standard form.
\frac{-y}{-1}=\frac{\frac{5x}{4}+2}{-1}
Divide both sides by -1.
y=\frac{\frac{5x}{4}+2}{-1}
Dividing by -1 undoes the multiplication by -1.
y=-\frac{5x}{4}-2
Divide 2+\frac{5x}{4} by -1.
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