Solve -4/3b-2/3>1

$$- \frac { 4 } { 3 } b - \frac { 2 } { 3 } > 1$$

Solve for b

$$b<-\frac{5}{4}$$

Solution Steps

Add \frac{2}{3} to both sides.

$$-\frac{4}{3}b>1+\frac{2}{3}$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{4}{3}b>\frac{3}{3}+\frac{2}{3}$$

Since \frac{3}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$-\frac{4}{3}b>\frac{3+2}{3}$$

Add 3 and 2 to get 5.

$$-\frac{4}{3}b>\frac{5}{3}$$

Multiply both sides by -\frac{3}{4}, the reciprocal of -\frac{4}{3}. Since -\frac{4}{3} is negative, the inequality direction is changed.

$$b<\frac{5}{3}\left(-\frac{3}{4}\right)$$

Multiply \frac{5}{3} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$b<\frac{5\left(-3\right)}{3\times 4}$$

Do the multiplications in the fraction \frac{5\left(-3\right)}{3\times 4}.

$$b<\frac{-15}{12}$$

Reduce the fraction \frac{-15}{12} to lowest terms by extracting and canceling out 3.

$$b<-\frac{5}{4}$$