Solve -3/4d-6geq9

$$- \frac { 3 } { 4 } d - 6 \geq 9$$

Solve for d

$$d\leq -20$$

Solution Steps

Add 6 to both sides.

$$-\frac{3}{4}d\geq 9+6$$

Add 9 and 6 to get 15.

$$-\frac{3}{4}d\geq 15$$

Multiply both sides by -\frac{4}{3}, the reciprocal of -\frac{3}{4}. Since -\frac{3}{4} is negative, the inequality direction is changed.

$$d\leq 15\left(-\frac{4}{3}\right)$$

Express 15\left(-\frac{4}{3}\right) as a single fraction.

$$d\leq \frac{15\left(-4\right)}{3}$$

Multiply 15 and -4 to get -60.

$$d\leq \frac{-60}{3}$$

Divide -60 by 3 to get -20.

$$d\leq -20$$