Solve -3/4-(1-0.5)div1/3*[2+(-4)^2]

$$- \frac { 3 } { 4 } - ( 1 - 0.5 ) \div \frac { 1 } { 3 } \times [ 2 + ( - 4 ) ^ { 2 } ]$$

Evaluate

$$-27.75$$

Solution Steps

Subtract 0.5 from 1 to get 0.5.

$$-\frac{3}{4}-\frac{0.5}{\frac{1}{3}}\left(2+\left(-4\right)^{2}\right)$$

Divide 0.5 by \frac{1}{3} by multiplying 0.5 by the reciprocal of \frac{1}{3}.

$$-\frac{3}{4}-0.5\times 3\left(2+\left(-4\right)^{2}\right)$$

Multiply 0.5 and 3 to get 1.5.

$$-\frac{3}{4}-1.5\left(2+\left(-4\right)^{2}\right)$$

Calculate -4 to the power of 2 and get 16.

$$-\frac{3}{4}-1.5\left(2+16\right)$$

Add 2 and 16 to get 18.

$$-\frac{3}{4}-1.5\times 18$$

Multiply 1.5 and 18 to get 27.

$$-\frac{3}{4}-27$$

Convert 27 to fraction \frac{108}{4}.

$$-\frac{3}{4}-\frac{108}{4}$$

Since -\frac{3}{4} and \frac{108}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-108}{4}$$

Subtract 108 from -3 to get -111.

$$-\frac{111}{4}$$

Factor

$$-27.75$$