Solve -3/4*(-11/3-0.4+12)

$$- \frac { 3 } { 4 } \times ( - 1 \frac { 1 } { 3 } - 0.4 + 12 )$$

Evaluate

$$-7.7$$

Solution Steps

Multiply 1 and 3 to get 3.

$$-\frac{3}{4}\left(-\frac{3+1}{3}-0.4+12\right)$$

Add 3 and 1 to get 4.

$$-\frac{3}{4}\left(-\frac{4}{3}-0.4+12\right)$$

Convert decimal number 0.4 to fraction \frac{4}{10}. Reduce the fraction \frac{4}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{3}{4}\left(-\frac{4}{3}-\frac{2}{5}+12\right)$$

Least common multiple of 3 and 5 is 15. Convert -\frac{4}{3} and \frac{2}{5} to fractions with denominator 15.

$$-\frac{3}{4}\left(-\frac{20}{15}-\frac{6}{15}+12\right)$$

Since -\frac{20}{15} and \frac{6}{15} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{3}{4}\left(\frac{-20-6}{15}+12\right)$$

Subtract 6 from -20 to get -26.

$$-\frac{3}{4}\left(-\frac{26}{15}+12\right)$$

Convert 12 to fraction \frac{180}{15}.

$$-\frac{3}{4}\left(-\frac{26}{15}+\frac{180}{15}\right)$$

Since -\frac{26}{15} and \frac{180}{15} have the same denominator, add them by adding their numerators.

$$-\frac{3}{4}\times \frac{-26+180}{15}$$

Add -26 and 180 to get 154.

$$-\frac{3}{4}\times \frac{154}{15}$$

Multiply -\frac{3}{4} times \frac{154}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3\times 154}{4\times 15}$$

Do the multiplications in the fraction \frac{-3\times 154}{4\times 15}.

$$\frac{-462}{60}$$

Reduce the fraction \frac{-462}{60} to lowest terms by extracting and canceling out 6.

$$-\frac{77}{10}$$

Factor

$$-7.7$$