Solve -3/3-2*3^2-9+1/3-2*1-1

$$- \frac { 3 } { 3 } - 2 \cdot 3 ^ { 2 } - 9 + \frac { 1 } { 3 } - 2 \cdot 1 - 1$$

Evaluate

$$-\frac{92}{3}\approx -30.666666667$$

Solution Steps

Divide 3 by 3 to get 1.

$$-1-2\times 3^{2}-9+\frac{1}{3}-2\times 1-1$$

Calculate 3 to the power of 2 and get 9.

$$-1-2\times 9-9+\frac{1}{3}-2\times 1-1$$

Multiply 2 and 9 to get 18.

$$-1-18-9+\frac{1}{3}-2\times 1-1$$

Subtract 18 from -1 to get -19.

$$-19-9+\frac{1}{3}-2\times 1-1$$

Subtract 9 from -19 to get -28.

$$-28+\frac{1}{3}-2\times 1-1$$

Convert -28 to fraction -\frac{84}{3}.

$$-\frac{84}{3}+\frac{1}{3}-2\times 1-1$$

Since -\frac{84}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{-84+1}{3}-2\times 1-1$$

Add -84 and 1 to get -83.

$$-\frac{83}{3}-2\times 1-1$$

Multiply 2 and 1 to get 2.

$$-\frac{83}{3}-2-1$$

Convert 2 to fraction \frac{6}{3}.

$$-\frac{83}{3}-\frac{6}{3}-1$$

Since -\frac{83}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-83-6}{3}-1$$

Subtract 6 from -83 to get -89.

$$-\frac{89}{3}-1$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{89}{3}-\frac{3}{3}$$

Since -\frac{89}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-89-3}{3}$$

Subtract 3 from -89 to get -92.

$$-\frac{92}{3}$$

Factor

$$-\frac{92}{3} = -30\frac{2}{3} = -30.666666666666668$$