Solve for a
a=12
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-\frac{2}{3}a+10-\frac{2}{3}a=-6
Subtract \frac{2}{3}a from both sides.
-\frac{4}{3}a+10=-6
Combine -\frac{2}{3}a and -\frac{2}{3}a to get -\frac{4}{3}a.
-\frac{4}{3}a=-6-10
Subtract 10 from both sides.
-\frac{4}{3}a=-16
Subtract 10 from -6 to get -16.
a=-16\left(-\frac{3}{4}\right)
Multiply both sides by -\frac{3}{4}, the reciprocal of -\frac{4}{3}.
a=\frac{-16\left(-3\right)}{4}
Express -16\left(-\frac{3}{4}\right) as a single fraction.
a=\frac{48}{4}
Multiply -16 and -3 to get 48.
a=12
Divide 48 by 4 to get 12.
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