Solve -16/6-19/6=1

$$- \frac { 16 } { 6 } - \frac { 19 } { 6 } = 1$$

Verify

Solution Steps

Reduce the fraction \frac{16}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{8}{3}-\frac{19}{6}=1$$

Least common multiple of 3 and 6 is 6. Convert -\frac{8}{3} and \frac{19}{6} to fractions with denominator 6.

$$-\frac{16}{6}-\frac{19}{6}=1$$

Since -\frac{16}{6} and \frac{19}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-16-19}{6}=1$$

Subtract 19 from -16 to get -35.

$$-\frac{35}{6}=1$$

Convert 1 to fraction \frac{6}{6}.

$$-\frac{35}{6}=\frac{6}{6}$$

Compare -\frac{35}{6} and \frac{6}{6}.

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