Solve -100/3t+20>40t

$$- \frac { 100 } { 3 } t + 20 > 40 t$$

Solve for t

$$t<\frac{3}{11}$$

Solution Steps

Subtract 40t from both sides.

$$-\frac{100}{3}t+20-40t>0$$

Combine -\frac{100}{3}t and -40t to get -\frac{220}{3}t.

$$-\frac{220}{3}t+20>0$$

Subtract 20 from both sides. Anything subtracted from zero gives its negation.

$$-\frac{220}{3}t>-20$$

Multiply both sides by -\frac{3}{220}, the reciprocal of -\frac{220}{3}. Since -\frac{220}{3} is negative, the inequality direction is changed.

$$t<-20\left(-\frac{3}{220}\right)$$

Express -20\left(-\frac{3}{220}\right) as a single fraction.

$$t<\frac{-20\left(-3\right)}{220}$$

Multiply -20 and -3 to get 60.

$$t<\frac{60}{220}$$

Reduce the fraction \frac{60}{220} to lowest terms by extracting and canceling out 20.

$$t<\frac{3}{11}$$