Solve -1/24-[1/18+(3/4*2/8)^2]

$$- \frac { 1 } { 24 } - [ \frac { 1 } { 18 } + ( \frac { 3 } { 4 } \cdot \frac { 2 } { 8 } ) ^ { 2 } ]$$

Evaluate

$$-\frac{305}{2304}\approx -0.132378472$$

Solution Steps

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{24}-\left(\frac{1}{18}+\left(\frac{3}{4}\times \frac{1}{4}\right)^{2}\right)$$

Multiply \frac{3}{4} and \frac{1}{4} to get \frac{3}{16}.

$$-\frac{1}{24}-\left(\frac{1}{18}+\left(\frac{3}{16}\right)^{2}\right)$$

Calculate \frac{3}{16} to the power of 2 and get \frac{9}{256}.

$$-\frac{1}{24}-\left(\frac{1}{18}+\frac{9}{256}\right)$$

Add \frac{1}{18} and \frac{9}{256} to get \frac{209}{2304}.

$$-\frac{1}{24}-\frac{209}{2304}$$

Subtract \frac{209}{2304} from -\frac{1}{24} to get -\frac{305}{2304}.

$$-\frac{305}{2304}$$

Factor

$$-\frac{305}{2304} = -0.1323784722222222$$