Solve -1/2(2x-10y-3)=-1x+10y

$$- \frac { 1 } { 2 } ( 2 x - 10 y - 3 ) = - 1 x + 10 y$$

Solve for y

$$y = \frac{3}{10} = 0.3$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{1}{2} by 2x-10y-3.

$$-x+5y+\frac{3}{2}=-x+10y$$

Subtract 10y from both sides.

$$-x+5y+\frac{3}{2}-10y=-x$$

Combine 5y and -10y to get -5y.

$$-x-5y+\frac{3}{2}=-x$$

Add x to both sides.

$$-5y+\frac{3}{2}=-x+x$$

Combine -x and x to get 0.

$$-5y+\frac{3}{2}=0$$

Subtract \frac{3}{2} from both sides. Anything subtracted from zero gives its negation.

$$-5y=-\frac{3}{2}$$

Divide both sides by -5.

$$y=\frac{-\frac{3}{2}}{-5}$$

Express \frac{-\frac{3}{2}}{-5} as a single fraction.

$$y=\frac{-3}{2\left(-5\right)}$$

Multiply 2 and -5 to get -10.

$$y=\frac{-3}{-10}$$

Fraction \frac{-3}{-10} can be simplified to \frac{3}{10} by removing the negative sign from both the numerator and the denominator.

$$y=\frac{3}{10}$$

Solve for x (complex solution)

$$x\in \mathrm{C}$$

$$y = \frac{3}{10} = 0.3$$

Solve for x

$$x\in \mathrm{R}$$

$$y = \frac{3}{10} = 0.3$$