Solve -(25/6)+sqrt{frac{289/36}}{2.1}=

$$- \frac { ( \frac { 25 } { 6 } ) + \sqrt { \frac { 289 } { 36 } } } { 2.1 } =$$

Evaluate

$$-\frac{10}{3}\approx -3.333333333$$

Solution Steps

Rewrite the square root of the division \frac{289}{36} as the division of square roots \frac{\sqrt{289}}{\sqrt{36}}. Take the square root of both numerator and denominator.

$$-\frac{\frac{25}{6}+\frac{17}{6}}{2.1}$$

Since \frac{25}{6} and \frac{17}{6} have the same denominator, add them by adding their numerators.

$$-\frac{\frac{25+17}{6}}{2.1}$$

Add 25 and 17 to get 42.

$$-\frac{\frac{42}{6}}{2.1}$$

Divide 42 by 6 to get 7.

$$-\frac{7}{2.1}$$

Expand \frac{7}{2.1} by multiplying both numerator and the denominator by 10.

$$-\frac{70}{21}$$

Reduce the fraction \frac{70}{21} to lowest terms by extracting and canceling out 7.

$$-\frac{10}{3}$$

Factor

$$-\frac{10}{3} = -3\frac{1}{3} = -3.3333333333333335$$