Evaluate
\frac{3}{7}\approx 0.428571429
Factor
\frac{3}{7} = 0.42857142857142855
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-\frac{\left(\frac{10}{9}\right)^{2}}{\left(1-\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Add \frac{1}{3} and \frac{7}{9} to get \frac{10}{9}.
-\frac{\frac{100}{81}}{\left(1-\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Calculate \frac{10}{9} to the power of 2 and get \frac{100}{81}.
-\frac{\frac{100}{81}}{\left(\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Subtract \frac{1}{2} from 1 to get \frac{1}{2}.
-\frac{\frac{100}{81}}{\frac{1}{4}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.
-\frac{\frac{100}{81}}{\frac{1}{4}\left(-8\right)-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Calculate -2 to the power of 3 and get -8.
-\frac{\frac{100}{81}}{-2-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Multiply \frac{1}{4} and -8 to get -2.
-\frac{\frac{100}{81}}{-\frac{7}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Subtract \frac{3}{2} from -2 to get -\frac{7}{2}.
-\frac{100}{81}\left(-\frac{2}{7}\right)+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Divide \frac{100}{81} by -\frac{7}{2} by multiplying \frac{100}{81} by the reciprocal of -\frac{7}{2}.
-\left(-\frac{200}{567}\right)+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Multiply \frac{100}{81} and -\frac{2}{7} to get -\frac{200}{567}.
\frac{200}{567}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
The opposite of -\frac{200}{567} is \frac{200}{567}.
\frac{200}{567}+\left(-\frac{1}{36}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Calculate -\frac{1}{6} to the power of 2 and get \frac{1}{36}.
\frac{200}{567}+\left(-\frac{1}{36}+\frac{\frac{1}{20}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Subtract \frac{1}{5} from \frac{1}{4} to get \frac{1}{20}.
\frac{200}{567}+\left(-\frac{1}{36}+\frac{\frac{1}{20}}{\left(\frac{3}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Subtract \frac{2}{5} from 1 to get \frac{3}{5}.
\frac{200}{567}+\left(-\frac{1}{36}+\frac{\frac{1}{20}}{\frac{9}{25}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Calculate \frac{3}{5} to the power of 2 and get \frac{9}{25}.
\frac{200}{567}+\left(-\frac{1}{36}+\frac{1}{20}\times \frac{25}{9}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Divide \frac{1}{20} by \frac{9}{25} by multiplying \frac{1}{20} by the reciprocal of \frac{9}{25}.
\frac{200}{567}+\left(-\frac{1}{36}+\frac{5}{36}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Multiply \frac{1}{20} and \frac{25}{9} to get \frac{5}{36}.
\frac{200}{567}+\left(\frac{1}{9}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Add -\frac{1}{36} and \frac{5}{36} to get \frac{1}{9}.
\frac{200}{567}+\frac{1}{81}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Calculate \frac{1}{9} to the power of 2 and get \frac{1}{81}.
\frac{23}{63}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}
Add \frac{200}{567} and \frac{1}{81} to get \frac{23}{63}.
\frac{23}{63}-\frac{\frac{1}{9}}{\frac{1}{8}-\frac{15}{8}}
Subtract \frac{2}{9} from \frac{1}{3} to get \frac{1}{9}.
\frac{23}{63}-\frac{\frac{1}{9}}{-\frac{7}{4}}
Subtract \frac{15}{8} from \frac{1}{8} to get -\frac{7}{4}.
\frac{23}{63}-\frac{1}{9}\left(-\frac{4}{7}\right)
Divide \frac{1}{9} by -\frac{7}{4} by multiplying \frac{1}{9} by the reciprocal of -\frac{7}{4}.
\frac{23}{63}-\left(-\frac{4}{63}\right)
Multiply \frac{1}{9} and -\frac{4}{7} to get -\frac{4}{63}.
\frac{23}{63}+\frac{4}{63}
The opposite of -\frac{4}{63} is \frac{4}{63}.
\frac{3}{7}
Add \frac{23}{63} and \frac{4}{63} to get \frac{3}{7}.
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Simultaneous equation
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Differentiation
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Integration
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Limits
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