Solve -[-(1)^2/2+3/4(1)^3+1]

$$- [ - \frac { ( 1 ) ^ { 2 } } { 2 } + \frac { 3 } { 4 } ( 1 ) ^ { 3 } + 1 ]$$

Evaluate

$$-\frac{5}{4}=-1.25$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$-\left(-\frac{1}{2}+\frac{3}{4}\times 1^{3}+1\right)$$

Calculate 1 to the power of 3 and get 1.

$$-\left(-\frac{1}{2}+\frac{3}{4}\times 1+1\right)$$

Multiply \frac{3}{4} and 1 to get \frac{3}{4}.

$$-\left(-\frac{1}{2}+\frac{3}{4}+1\right)$$

Least common multiple of 2 and 4 is 4. Convert -\frac{1}{2} and \frac{3}{4} to fractions with denominator 4.

$$-\left(-\frac{2}{4}+\frac{3}{4}+1\right)$$

Since -\frac{2}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$-\left(\frac{-2+3}{4}+1\right)$$

Add -2 and 3 to get 1.

$$-\left(\frac{1}{4}+1\right)$$

Convert 1 to fraction \frac{4}{4}.

$$-\left(\frac{1}{4}+\frac{4}{4}\right)$$

Since \frac{1}{4} and \frac{4}{4} have the same denominator, add them by adding their numerators.

$$-\frac{1+4}{4}$$

Add 1 and 4 to get 5.

$$-\frac{5}{4}$$

Factor

$$-\frac{5}{4} = -1\frac{1}{4} = -1.25$$