Solve (x-7)div3/7+21=63

$$(x-7) \div \frac{ 3 }{ 7 } +21=63$$

Solve for x

$$x=25$$

Steps for Solving Linear Equation

Divide each term of x-7 by \frac{3}{7} to get \frac{x}{\frac{3}{7}}+\frac{-7}{\frac{3}{7}}.

$$\frac{x}{\frac{3}{7}}+\frac{-7}{\frac{3}{7}}+21=63$$

Divide -7 by \frac{3}{7} by multiplying -7 by the reciprocal of \frac{3}{7}.

$$\frac{x}{\frac{3}{7}}-7\times \frac{7}{3}+21=63$$

Express -7\times \frac{7}{3} as a single fraction.

$$\frac{x}{\frac{3}{7}}+\frac{-7\times 7}{3}+21=63$$

Multiply -7 and 7 to get -49.

$$\frac{x}{\frac{3}{7}}+\frac{-49}{3}+21=63$$

Fraction \frac{-49}{3} can be rewritten as -\frac{49}{3} by extracting the negative sign.

$$\frac{x}{\frac{3}{7}}-\frac{49}{3}+21=63$$

Convert 21 to fraction \frac{63}{3}.

$$\frac{x}{\frac{3}{7}}-\frac{49}{3}+\frac{63}{3}=63$$

Since -\frac{49}{3} and \frac{63}{3} have the same denominator, add them by adding their numerators.

$$\frac{x}{\frac{3}{7}}+\frac{-49+63}{3}=63$$

Add -49 and 63 to get 14.

$$\frac{x}{\frac{3}{7}}+\frac{14}{3}=63$$

Subtract \frac{14}{3} from both sides.

$$\frac{x}{\frac{3}{7}}=63-\frac{14}{3}$$

Convert 63 to fraction \frac{189}{3}.

$$\frac{x}{\frac{3}{7}}=\frac{189}{3}-\frac{14}{3}$$

Since \frac{189}{3} and \frac{14}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x}{\frac{3}{7}}=\frac{189-14}{3}$$

Subtract 14 from 189 to get 175.

$$\frac{x}{\frac{3}{7}}=\frac{175}{3}$$

Multiply both sides by \frac{3}{7}.

$$x=\frac{175}{3}\times \frac{3}{7}$$

Multiply \frac{175}{3} times \frac{3}{7} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{175\times 3}{3\times 7}$$

Cancel out 3 in both numerator and denominator.

$$x=\frac{175}{7}$$

Divide 175 by 7 to get 25.

$$x=25$$