Solve (x-5)div(-4-5)=(y-3)div(15-3)

$$(x-5) \div (-4-5)=(y-3) \div (15-3)$$

Solve for x

$$x=\frac{29-3y}{4}$$

Steps for Solving Linear Equation

Subtract 5 from -4 to get -9.

$$\frac{x-5}{-9}=\frac{y-3}{15-3}$$

Multiply both numerator and denominator by -1.

$$\frac{-x+5}{9}=\frac{y-3}{15-3}$$

Subtract 3 from 15 to get 12.

$$\frac{-x+5}{9}=\frac{y-3}{12}$$

Divide each term of -x+5 by 9 to get -\frac{1}{9}x+\frac{5}{9}.

$$-\frac{1}{9}x+\frac{5}{9}=\frac{y-3}{12}$$

Divide each term of y-3 by 12 to get \frac{1}{12}y-\frac{1}{4}.

$$-\frac{1}{9}x+\frac{5}{9}=\frac{1}{12}y-\frac{1}{4}$$

Subtract \frac{5}{9} from both sides.

$$-\frac{1}{9}x=\frac{1}{12}y-\frac{1}{4}-\frac{5}{9}$$

Subtract \frac{5}{9} from -\frac{1}{4} to get -\frac{29}{36}.

$$-\frac{1}{9}x=\frac{1}{12}y-\frac{29}{36}$$

The equation is in standard form.

$$-\frac{1}{9}x=\frac{y}{12}-\frac{29}{36}$$

Multiply both sides by -9.

$$\frac{-\frac{1}{9}x}{-\frac{1}{9}}=\frac{\frac{y}{12}-\frac{29}{36}}{-\frac{1}{9}}$$

Dividing by -\frac{1}{9} undoes the multiplication by -\frac{1}{9}.

$$x=\frac{\frac{y}{12}-\frac{29}{36}}{-\frac{1}{9}}$$

Divide \frac{y}{12}-\frac{29}{36} by -\frac{1}{9} by multiplying \frac{y}{12}-\frac{29}{36} by the reciprocal of -\frac{1}{9}.

$$x=\frac{29-3y}{4}$$

Solve for y

$$y=\frac{29-4x}{3}$$

Steps for Solving Linear Equation

Subtract 5 from -4 to get -9.

$$\frac{x-5}{-9}=\frac{y-3}{15-3}$$

Multiply both numerator and denominator by -1.

$$\frac{-x+5}{9}=\frac{y-3}{15-3}$$

Subtract 3 from 15 to get 12.

$$\frac{-x+5}{9}=\frac{y-3}{12}$$

Divide each term of -x+5 by 9 to get -\frac{1}{9}x+\frac{5}{9}.

$$-\frac{1}{9}x+\frac{5}{9}=\frac{y-3}{12}$$

Divide each term of y-3 by 12 to get \frac{1}{12}y-\frac{1}{4}.

$$-\frac{1}{9}x+\frac{5}{9}=\frac{1}{12}y-\frac{1}{4}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{12}y-\frac{1}{4}=-\frac{1}{9}x+\frac{5}{9}$$

Add \frac{1}{4} to both sides.

$$\frac{1}{12}y=-\frac{1}{9}x+\frac{5}{9}+\frac{1}{4}$$

Add \frac{5}{9} and \frac{1}{4} to get \frac{29}{36}.

$$\frac{1}{12}y=-\frac{1}{9}x+\frac{29}{36}$$

The equation is in standard form.

$$\frac{1}{12}y=-\frac{x}{9}+\frac{29}{36}$$

Multiply both sides by 12.

$$\frac{\frac{1}{12}y}{\frac{1}{12}}=\frac{-\frac{x}{9}+\frac{29}{36}}{\frac{1}{12}}$$

Dividing by \frac{1}{12} undoes the multiplication by \frac{1}{12}.

$$y=\frac{-\frac{x}{9}+\frac{29}{36}}{\frac{1}{12}}$$

Divide -\frac{x}{9}+\frac{29}{36} by \frac{1}{12} by multiplying -\frac{x}{9}+\frac{29}{36} by the reciprocal of \frac{1}{12}.

$$y=\frac{29-4x}{3}$$