Solve (x-5*5-2*8)+6*5-5*10=6div2

$$(x-5 \times 5-2 \times 8)+6 \times 5-5 \times 10=6 \div 2$$

Solve for x

$$x=64$$

Steps for Solving Linear Equation

Multiply 5 and 5 to get 25.

$$x-25-2\times 8+6\times 5-5\times 10=\frac{6}{2}$$

Multiply 2 and 8 to get 16.

$$x-25-16+6\times 5-5\times 10=\frac{6}{2}$$

Subtract 16 from -25 to get -41.

$$x-41+6\times 5-5\times 10=\frac{6}{2}$$

Multiply 6 and 5 to get 30.

$$x-41+30-5\times 10=\frac{6}{2}$$

Add -41 and 30 to get -11.

$$x-11-5\times 10=\frac{6}{2}$$

Multiply 5 and 10 to get 50.

$$x-11-50=\frac{6}{2}$$

Subtract 50 from -11 to get -61.

$$x-61=\frac{6}{2}$$

Divide 6 by 2 to get 3.

$$x-61=3$$

Add 61 to both sides.

$$x=3+61$$

Add 3 and 61 to get 64.

$$x=64$$