Solve (x-3)(x+4)=(x-1)(x+5)-1

$$(x-3)(x+4)=(x-1)(x+5)-1$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Use the distributive property to multiply x-3 by x+4 and combine like terms.

$$x^{2}+x-12=\left(x-1\right)\left(x+5\right)-1$$

Use the distributive property to multiply x-1 by x+5 and combine like terms.

$$x^{2}+x-12=x^{2}+4x-5-1$$

Subtract 1 from -5 to get -6.

$$x^{2}+x-12=x^{2}+4x-6$$

Subtract x^{2} from both sides.

$$x^{2}+x-12-x^{2}=4x-6$$

Combine x^{2} and -x^{2} to get 0.

$$x-12=4x-6$$

Subtract 4x from both sides.

$$x-12-4x=-6$$

Combine x and -4x to get -3x.

$$-3x-12=-6$$

Add 12 to both sides.

$$-3x=-6+12$$

Add -6 and 12 to get 6.

$$-3x=6$$

Divide both sides by -3.

$$x=\frac{6}{-3}$$

Divide 6 by -3 to get -2.

$$x=-2$$