Solve (x-3)+(x+y)=0

$$(x-3)+(x+y)=0$$

Solve for x

$$x=\frac{3-y}{2}$$

Steps for Solving Linear Equation

Combine x and x to get 2x.

$$2x-3+y=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$2x+y=3$$

Subtract y from both sides.

$$2x=3-y$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{3-y}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{3-y}{2}$$

Solve for y

$$y=3-2x$$

Solution Steps

Combine x and x to get 2x.

$$2x-3+y=0$$

Subtract 2x from both sides. Anything subtracted from zero gives its negation.

$$-3+y=-2x$$

Add 3 to both sides.

$$y=-2x+3$$