Solve (x+4)*(x+4)=x^2+60

$$(x+4) \times (x+4)= { x }^{ 2 } +60$$

Solve for x

$$x = \frac{11}{2} = 5\frac{1}{2} = 5.5$$

Steps for Solving Linear Equation

Multiply x+4 and x+4 to get \left(x+4\right)^{2}.

$$\left(x+4\right)^{2}=x^{2}+60$$

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+4\right)^{2}.

$$x^{2}+8x+16=x^{2}+60$$

Subtract x^{2} from both sides.

$$x^{2}+8x+16-x^{2}=60$$

Combine x^{2} and -x^{2} to get 0.

$$8x+16=60$$

Subtract 16 from both sides.

$$8x=60-16$$

Subtract 16 from 60 to get 44.

$$8x=44$$

Divide both sides by 8.

$$x=\frac{44}{8}$$

Reduce the fraction \frac{44}{8} to lowest terms by extracting and canceling out 4.

$$x=\frac{11}{2}$$