Solve (x+1)(x-0)(x-1)(x-3)

$$(x+1)(x-0)(x-1)(x-3)$$

Evaluate

$$x\left(x-3\right)\left(x^{2}-1\right)$$

Solution Steps

Use the distributive property to multiply x+1 by x-0.

$$\left(x\left(x-0\right)+x-0\right)\left(x-1\right)\left(x-3\right)$$

Apply the distributive property by multiplying each term of x\left(x-0\right)+x-0 by each term of x-1.

$$\left(\left(x-0\right)x^{2}-x\left(x-0\right)+\left(x-0\right)x-\left(x-0\right)\right)\left(x-3\right)$$

Combine -x\left(x-0\right) and \left(x-0\right)x to get 0.

$$\left(\left(x-0\right)x^{2}-\left(x-0\right)\right)\left(x-3\right)$$

Apply the distributive property by multiplying each term of \left(x-0\right)x^{2}-\left(x-0\right) by each term of x-3.

$$\left(x-0\right)x^{3}-3\left(x-0\right)x^{2}-\left(x-0\right)x+3\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$\left(x+0\right)x^{3}-3\left(x-0\right)x^{2}-\left(x-0\right)x+3\left(x-0\right)$$

Anything plus zero gives itself.

$$xx^{3}-3\left(x-0\right)x^{2}-\left(x-0\right)x+3\left(x-0\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$x^{4}-3\left(x-0\right)x^{2}-\left(x-0\right)x+3\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{4}-3xx^{2}-\left(x-0\right)x+3\left(x-0\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$x^{4}-3x^{3}-\left(x-0\right)x+3\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{4}-3x^{3}-xx+3\left(x-0\right)$$

Multiply x and x to get x^{2}.

$$x^{4}-3x^{3}-x^{2}+3\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{4}-3x^{3}-x^{2}+3\left(x+0\right)$$

Anything plus zero gives itself.

$$x^{4}-3x^{3}-x^{2}+3x$$

Expand

$$x^{4}-3x^{3}-x^{2}+3x$$

Solution Steps

Use the distributive property to multiply x+1 by x-0.

$$\left(x\left(x-0\right)+x-0\right)\left(x-1\right)\left(x-3\right)$$

Apply the distributive property by multiplying each term of x\left(x-0\right)+x-0 by each term of x-1.

$$\left(\left(x-0\right)x^{2}-x\left(x-0\right)+\left(x-0\right)x-\left(x-0\right)\right)\left(x-3\right)$$

Combine -x\left(x-0\right) and \left(x-0\right)x to get 0.

$$\left(\left(x-0\right)x^{2}-\left(x-0\right)\right)\left(x-3\right)$$

Apply the distributive property by multiplying each term of \left(x-0\right)x^{2}-\left(x-0\right) by each term of x-3.

$$\left(x-0\right)x^{3}-3\left(x-0\right)x^{2}-\left(x-0\right)x+3\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$\left(x+0\right)x^{3}-3\left(x-0\right)x^{2}-\left(x-0\right)x+3\left(x-0\right)$$

Anything plus zero gives itself.

$$xx^{3}-3\left(x-0\right)x^{2}-\left(x-0\right)x+3\left(x-0\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$x^{4}-3\left(x-0\right)x^{2}-\left(x-0\right)x+3\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{4}-3xx^{2}-\left(x-0\right)x+3\left(x-0\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$x^{4}-3x^{3}-\left(x-0\right)x+3\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{4}-3x^{3}-xx+3\left(x-0\right)$$

Multiply x and x to get x^{2}.

$$x^{4}-3x^{3}-x^{2}+3\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{4}-3x^{3}-x^{2}+3\left(x+0\right)$$

Anything plus zero gives itself.

$$x^{4}-3x^{3}-x^{2}+3x$$