Solve (x+1)(x+1)(x-2)=-y

$$(x+1)(x+1)(x-2)=-y$$

Solve for y

$$y=-\left(x-2\right)\left(x+1\right)^{2}$$

Steps for Solving Linear Equation

Multiply x+1 and x+1 to get \left(x+1\right)^{2}.

$$\left(x+1\right)^{2}\left(x-2\right)=-y$$

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.

$$\left(x^{2}+2x+1\right)\left(x-2\right)=-y$$

Use the distributive property to multiply x^{2}+2x+1 by x-2 and combine like terms.

$$x^{3}-3x-2=-y$$

Swap sides so that all variable terms are on the left hand side.

$$-y=x^{3}-3x-2$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{\left(x-2\right)\left(x+1\right)^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{\left(x-2\right)\left(x+1\right)^{2}}{-1}$$

Divide \left(-2+x\right)\left(1+x\right)^{2} by -1.

$$y=-\left(x-2\right)\left(x+1\right)^{2}$$