Solve (9div5)(x+(7div2))=(129div20)+1.2x

$$(9 \div 5)(x+(7 \div 2))=(129 \div 20)+1.2x$$

Solve for x

$$x=0.25$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{9}{5} by x+\frac{7}{2}.

$$\frac{9}{5}x+\frac{9}{5}\times \frac{7}{2}=\frac{129}{20}+1.2x$$

Multiply \frac{9}{5} times \frac{7}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9}{5}x+\frac{9\times 7}{5\times 2}=\frac{129}{20}+1.2x$$

Do the multiplications in the fraction \frac{9\times 7}{5\times 2}.

$$\frac{9}{5}x+\frac{63}{10}=\frac{129}{20}+1.2x$$

Subtract 1.2x from both sides.

$$\frac{9}{5}x+\frac{63}{10}-1.2x=\frac{129}{20}$$

Combine \frac{9}{5}x and -1.2x to get \frac{3}{5}x.

$$\frac{3}{5}x+\frac{63}{10}=\frac{129}{20}$$

Subtract \frac{63}{10} from both sides.

$$\frac{3}{5}x=\frac{129}{20}-\frac{63}{10}$$

Least common multiple of 20 and 10 is 20. Convert \frac{129}{20} and \frac{63}{10} to fractions with denominator 20.

$$\frac{3}{5}x=\frac{129}{20}-\frac{126}{20}$$

Since \frac{129}{20} and \frac{126}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{5}x=\frac{129-126}{20}$$

Subtract 126 from 129 to get 3.

$$\frac{3}{5}x=\frac{3}{20}$$

Multiply both sides by \frac{5}{3}, the reciprocal of \frac{3}{5}.

$$x=\frac{3}{20}\times \frac{5}{3}$$

Multiply \frac{3}{20} times \frac{5}{3} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{3\times 5}{20\times 3}$$

Cancel out 3 in both numerator and denominator.

$$x=\frac{5}{20}$$

Reduce the fraction \frac{5}{20} to lowest terms by extracting and canceling out 5.

$$x=\frac{1}{4}$$